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The equations of motion under constant acceleration are:

Vf = Vi + A T
D = Vi T + (1/2) A T^2

where:
T is the time interval
A is the acceleration
Vi is the initial velocity
Vf is the final velocity

So, you can find A because in 6 seconds (T = 6) the car goes from a standing start (Vi = 0) and covers 100 meters, so you have all the parameters for the distance equation.

From the velocity equation, you can determine its Vf after that period of acceleration.

Using the velocity equation you can also find the times at which it is going 60 m/s and 80 m/s. Given the time interval, you can then use the distance equation to get the distance travelled.
Etc.