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How much time does it take for the Porsche to catch the Honda?

Two cars, a Porsche and a Honda, are traveling in the same direction, although the Porsche is 184 m behind the Honda. The speed of the Porsche is 23.9 m/s and the speed of the Honda is 17.9 m/s. How much time does it take for the Porsche to catch the Honda? [Hint: What must be true about the displacements of the two cars when they meet?]



 

3 Users Response In " How much time does it take for the Porsche to catch the Honda? "

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Slaggers says in February 28th 2010 at 6:59 pm    

Hey!

Here’s the entire answer to your question.

Let’s first identify the values we’re given:

d = distance Porsche is behind Honda = 184 m

V = speed of Porsche = 23.9 m/s

v = speed of Honda = 17.9 m/s

The “hint” in the problem asks what must be true about the displacements of the cars when they meet? Well, the displacements must be EQUAL if they meet:

displacement of Honda = displacement of Porsche

or

d(Honda) = d(Porsche)

Now let’s figure out what these displacements are. Assume that the INITIAL position of the Porsche is d = 0. Then:

d(Honda) = d + v*t

d(Porsche) = V*t

Now we equate these two values:

d + v*t = V*t

Here t = time, which is what we’re solving for. Rearranging terms to solve for t:

t = d / (V-v)

= 184 m / (23.9 m/s – 17.9 m/s)

= 30.66 seconds

So the Porsche will catch up to the Honda in 30.66 seconds. That’s your answer!

anaGah.

lunar_rick says in February 28th 2010 at 7:37 pm    

The basic formula would be vp * t = vh * t + x
Rewrite as t = x / (vp – vh) = 184 / (23.9 – 17.9) = 184 / 6 = 30.6 seconds.

leomir says in February 28th 2010 at 8:25 pm    

Tiempo de alcance:

Ta = d / ( V1 – V2)…………………( V1 > V2 )

Ta = 184 / (23,9 – 17,9) = 30,67s

Suerte!!! consultas: mir_urss@hotmail.com

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